2x^2+3y^3-4x^2=

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Solution for 2x^2+3y^3-4x^2= equation:


Simplifying
2x2 + 3y3 + -4x2 = 0

Reorder the terms:
2x2 + -4x2 + 3y3 = 0

Combine like terms: 2x2 + -4x2 = -2x2
-2x2 + 3y3 = 0

Solving
-2x2 + 3y3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3y3' to each side of the equation.
-2x2 + 3y3 + -3y3 = 0 + -3y3

Combine like terms: 3y3 + -3y3 = 0
-2x2 + 0 = 0 + -3y3
-2x2 = 0 + -3y3
Remove the zero:
-2x2 = -3y3

Divide each side by '-2'.
x2 = 1.5y3

Simplifying
x2 = 1.5y3

Combine like terms: 1.5y3 + -1.5y3 = 0.0
x2 + -1.5y3 = 0.0

The solution to this equation could not be determined.

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